# ch16-p066 - t(where x is in centimeters and t is in seconds...

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(d) The leading edge of the pulse reaches x = 10 cm at t = (10 – 4.0)/5 = 1.2 s. The particle (say, of the string that carries the pulse) at that location reaches a maximum displacement h = 2 cm at t = (10 – 3.0)/5 = 1.4 s. Finally, the trailing edge of the pulse departs from x = 10 cm at t = (10 – 1.0)/5 = 1.8 s. Thus, we find for h ( t ) at x = 10 cm (with the horizontal axis, t , in seconds): 66. (a) Recalling the discussion in §16-5, we see that the speed of the wave given by a function with argument x – 5.0
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Unformatted text preview: t (where x is in centimeters and t is in seconds) must be 5.0 cm/s . (b) In part (c), we show several “snapshots” of the wave: the one on the left is as shown in Figure 16–48 (at t = 0), the middle one is at t = 1.0 s, and the rightmost one is at 2.0 s t = . It is clear that the wave is traveling to the right (the + x direction). (c) The third picture in the sequence below shows the pulse at 2.0 s. The horizontal scale (and, presumably, the vertical one also) is in centimeters....
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## This note was uploaded on 04/16/2011 for the course PHYSICS 191262 taught by Professor Najafzadeh during the Spring '09 term at The Petroleum Institute.

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