(f) The speed of the wave is 2510rad s40m s.62.8rad/mvTkωλ====70. We write the expression for the displacement in the form y(x, t) = ymsin(kx– t).(a) The amplitude is ym= 2.0 cm = 0.020 m, as given in the problem. (b) The angular wave number kis k= 2π/λ= 2π/(0.10 m) = 63 m–1(c) The angular frequency is = 2πf= 2π(400 Hz) = 2510 rad/s = 2.5×103rad/s. (d) A minus sign is used before the tterm in the argument of the sine function because
This is the end of the preview. Sign up
access the rest of the document.