(f) The speed of the wave is
2510rad s
40m s.
62.8rad/m
v
Tk
ω
λ
===
=
70. We write the expression for the displacement in the form
y
(
x, t
) =
y
m
sin(
kx
–
t
).
(a) The amplitude is
y
m
= 2.0 cm = 0.020 m, as given in the problem.
(b) The angular wave number
k
is
k
= 2
π
/
λ
= 2
π
/(0.10 m) = 63 m
–1
(c) The angular frequency is
= 2
π
f
= 2
π
(400 Hz) = 2510 rad/s = 2.5
×
10
3
rad/s.
(d) A minus sign is used before the
t
term in the argument of the sine function because
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This note was uploaded on 04/16/2011 for the course PHYSICS 191262 taught by Professor Najafzadeh during the Spring '09 term at The Petroleum Institute.
 Spring '09
 NAJAFZADEH
 mechanics

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