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76. (a) At x = 2.3 m and t = 0.16 s the displacement is () ( )() [ ] ( , ) 0.15sin 0.79 2.3 13 0.16 m = 0.039m. yxt =− − (b) We choose y m = 0.15 m, so that there would be nodes (where the wave amplitude is zero) in the string as a result. (c) The second wave must be traveling with the same speed and frequency. This implies 1 0.79 m k − = , (d) and 13 rad/s
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This note was uploaded on 04/16/2011 for the course PHYSICS 191262 taught by Professor Najafzadeh during the Spring '09 term at The Petroleum Institute.
- Spring '09