ch16-p088 - 88. (a) The frequency is f = 1/T = 1/4 Hz, so v...

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88. (a) The frequency is f = 1/ T = 1/4 Hz, so v = f λ = 5.0 cm/s. (b) We refer to the graph to see that the maximum transverse speed (which we will refer to as u m ) is 5.0 cm/s. Recalling from Ch. 11 the simple harmonic motion relation u m = y m ω = y m 2 π f , we have 1 5.0 2 3.2 cm. 4 mm yy §· ¡ = ¨¸ ©¹ (c) As already noted, f = 0.25 Hz. (d) Since k = 2 π / λ , we have k = 10 π rad/m. There must be a sign difference between the t and x terms in the argument in order for the wave to travel to the right. The figure shows that at
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This note was uploaded on 04/16/2011 for the course PHYSICS 191262 taught by Professor Najafzadeh during the Spring '09 term at The Petroleum Institute.

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