exam 1 - GENE 3200 Fall 2010 Bedell Exam 1 Sept 9 ID no....

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GENE 3200 – Fall 2010 – Bedell Exam 1 – Sept 9 ID no. 810__________ KEY ________________ 1 Write your ID number (810 number, NOT SSN) on every page. Write your initials on the first page only. All of the multiple choice questions have only one correct answer. The exam should be completed in ink. Regrades will not be given if you write in pencil. All requests to re-grade an exam must be made in writing to Dr. Bedell within 48 hours of the grades being posted on WebCT. 1. (1 pt) True or false . An individual with two different alleles of a gene is a homozygote. 2. (2 pts) Which statement best describes Mendel's Second Law? (a) Gene pairs on different chromosome pairs assort independently at meiosis . (b) Gene pairs on different chromosome pairs assort independently at mitosis . (c) The frequency of recombination between two genes increases with distance. (d) The frequency of recombination between two genes decreases with distance. 3. (2 pts) How many different genotypes of gametes would be produced by an AA Bb Cc Dd Ee person? Show your calculations. 1 x 2 x 2 x 2 x 2 = 16 4. (2 pts) In Drosophila eye shape is controlled by a single autosomal gene. The dominant allele ( N ) of this gene causes the normal, oval eye shape and the recessive allele ( n ) of this gene causes the abnormal, narrow eye shape. After doing a cross of Nn x nn , you obtain 6 progeny. What is the probability that all of the progeny will have narrow eyes? Show all of your calculations. 1/2 x 1/2 x 1/2 x 1/2 x 1/2 x 1/2 or (1/2) 6 5. You have a pure-breeding strain of mice with short tails and you cross that with another pure- breeding strain that has long tails. All of the F1 progeny of this cross had short tails. In the F2 progeny 91 mice had short tails and 29 had long tails. 5. (cont) (2 pts) What proportion of the F2 mice with short tails will breed true? (a) 1/2 (b) 1/3 (c) 1/4 (d) 3/4 (e) All of the F2 6. (2 pts) Among the dihybrid crosses below, which will give a 1:1:1:1 ratio of phenotypes in their offspring? (a) AA BB x aa bb (b) Aa BB x aa BB (c) Aa Bb x Aa Bb (d) AA bb x aa BB (e) Aa Bb x aa bb (f) None of the above 7. In humans there are three unlinked genes that express antigens on the surface of red blood cells and determine different blood types. The I gene has three alleles ( I A , I B and i ) that determine the ABO blood group system. I A and I B are codominant, and both I A and I B are completely dominant to i . The MN gene has two codominant alleles ( M and N ) that determine blood type M, N, or MN. The Rh gene has two alleles [ positive ( pos ) and negative ( neg )], with the pos allele completely dominant to the neg allele. Continued on next page.
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GENE 3200 – Fall 2010 – Bedell Exam 1 – Sept 9 ID no. 810__________ KEY ________________ 2 7. (cont) (3 pts) A woman with “O MN Rh pos” blood type has a child with “O N Rh neg” blood type. Of the following males, which is the biological father? Assume no involvement of the Bombay phenotype. (a)
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exam 1 - GENE 3200 Fall 2010 Bedell Exam 1 Sept 9 ID no....

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