Unformatted text preview: = 2 The average number of customers in the system is 2. D. The average time a customer spends waiting Wq = Lq/ =1.3333/0.4 = 3.3333 min. The average time a customer spends waiting is 3.3333 minutes. E. The average time a customer spends in the system W = Wq +1/ = 3.3333 +(1/0.6) = 5 min. The average time a customer spends in the system is 5 minutes. F. The probability that arriving customers will have to wait for service Pw =/=0.4/0.6 =0.6667 The probability that arriving customers will have to wait for service is 0.6667....
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This note was uploaded on 04/17/2011 for the course COMPUTER S 101 taught by Professor Xxx during the Spring '11 term at Holy Family University.
 Spring '11
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