Chapter101_A

# Chapter101_A - Chapter 10 Section A Mathcad Solutions 10.1...

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y 1 0.33 := T 100 degC := Guess: x 1 0.33 := P 100 kPa := Given x 1 Psat 1 T () 1x 1 Psat 2 T + P = x 1 Psat 1 T y 1 P = x 1 P Find x 1 P , := x 1 0.169 = Ans. P 92.156kPa = Ans. (c) Given: x 1 0.33 := P 120 kPa := Guess: y 1 0.5 := T 100 degC := Given x 1 Psat 1 T 1 Psat 2 T + P = x 1 Psat 1 T y 1 P = y 1 T Find y 1 T , := y 1 0.542 = Ans. T 103.307degC = Ans. Chapter 10 - Section A - Mathcad Solutions 10.1 Benzene: A 1 13.7819 := B 1 2726.81 := C 1 217.572 := Toluene: A 2 13.9320 := B 2 3056.96 := C 2 217.625 := Psat 1 T () e A 1 B 1 T degC C 1 + kPa := Psat 2 T A 2 B 2 T degC C 2 + kPa := (a) Given: x 1 0.33 := T 100 degC := Guess: y 1 0.5 := P 100 kPa := Given x 1 Psat 1 T 1 Psat 2 T + P = x 1 Psat 1 T y 1 P = y 1 P Find y 1 P , := y 1 0.545 = Ans. P 109.303kPa = Ans. (b) Given: 312

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x 1 y 1 Find x 1 y 1 , () := x 1 0.282 = Ans. y 1 0.484 = Ans. (f) z 1 0.33 := x 1 0.282 = y 1 0.484 = Guess: L 0.5 := V 0.5 := Given z 1 Lx 1 Vy 1 + = LV + 1 = L V Find L V , := Vapor Fraction: V 0.238 = Ans. Liquid Fraction: L 0.762 = Ans. (g) Benzene and toluene are both non-polar and similar in shape and size. Therefore one would expect little chemical interaction between the components. The temperature is high enough and pressure low enough to expect ideal behavior. (d) Given: y 1 0.33 := P 120 kPa := Guess: x 1 0.33 := T 100 degC := Given x 1 Psat 1 T 1x 1 Psat 2 T + P = x 1 Psat 1 T y 1 P = x 1 T Find x 1 T , := x 1 0.173 = Ans. T 109.131degC = Ans. (e) Given: T 105 degC := P 120 kPa := Guess: x 1 0.33 := y 1 0.5 := Given x 1 Psat 1 T 1 Psat 2 T + P = x 1 Psat 1 T y 1 P = 313
0 0.5 1 60 70 80 90 100 110 120 130 140 Tx 1 () 1 x 1 y' 1 x 1 , 0 0.5 1 0 50 100 150 Px 1 1 x 1 y 1 x 1 , x 1 0 0.05 , 1.0 .. := y' 1 x 1 x 1 Psat 1 1 x 1 Psat 1 1 1x 1 Psat 2 1 + := 1 root x 1 Psat 1 t 1 Psat 2 t + P' t , := t9 0 := Guess t for root function: P' 90 := T-x-y diagram: y 1 x 1 x 1 Psat 1 T 1 := 1 x 1 Psat 1 T 1 Psat 2 T + := T9 0 := P-x-y diagram: Psat 2 T ( ) exp A 2 B 2 TC 2 + := Psat 1 T ( ) exp A 1 B 1 1 + := C 2 212.300 := B 2 3259.93 := A 2 13.9726 := C 1 217.572 := B 1 2726.81 := A 1 13.7819 := Antoine coefficients: Benzene=1; Ethylbenzene=2 (a) Pressures in kPa; temperatures in degC 10.2 314

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0 0.5 1 70 77.5 85 92.5 100 107.5 115 122.5 130 Tx 1 () 1 x 1 y' 1 x 1 , 0 0.5 1 20 66.67 113.33 160 Px 1 1 x 1 y 1 x 1 , x 1 0 0.05 , 1.0 .. := y' 1 x 1 x 1 Psat 1 1 x 1 Psat 1 1 1x 1 Psat 2 1 + := 1 root x 1 Psat 1 t 1 Psat 2 t + P' t , := t9 0 := Guess t for root function: P' 90 := T-x-y diagram: y 1 x 1 x 1 Psat 1 T 1 := 1 x 1 Psat 1 T 1 Psat 2 T + := T9 0 := P-x-y diagram: Psat 2 T ( ) exp A 2 B 2 TC 2 + := Psat 1 T ( ) exp A 1 B 1 1 + := C 2 211.700 := B 2 3174.78 := A 2 13.8635 := C 1 218.265 := B 1 2723.73 := A 1 13.7965 := Antoine coefficients: 1-Chlorobutane=1; Chlorobenzene=2 (b) 315
0.45 0.5 0.55 0.6 0.65 0.7 0.75 0.8 0.85 0 0.5 1 Vz 1 () x 1 y 1 z 1 V is obviously linear in z1: 1 z 1 x 1 y 1 x 1 := z 1 x 1 x 1 0.01 + , y 1 .. := z 1 x 1 1V y 1 V + =

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## This note was uploaded on 04/18/2011 for the course CEM 497 taught by Professor Ku during the Spring '11 term at Punjab Engineering College.

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Chapter101_A - Chapter 10 Section A Mathcad Solutions 10.1...

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