Chap5evenanswers(2)

Chap5evenanswers(2) - 1 64(8 x 5 5 128(8 x 5 2 C 16 1 40(4 x-1 5 2 1 24(4 x-1 3 2 C 20 tan 2 x 2 C 24 e tan θ C 28(tan-1 x 3 3 C 56 tan 5 x 5 C

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. MATH 1042 Chapter 5 Even Homework Answers Section 5.2 14) Z 3 0 g ( t ) dt = 3 2 ; Z 5 3 g ( t ) dt = 0 50) 17 58) 4 Section 5.4 4) F (0) = 0; F 0 (0) = 0; F 0 (3) = 12 18) F ( x ) = Z x 4 e - t 2 dt 22) tan ± 1 1 + s 2 ² 24) A (2) = 4; A (3) = 13 2 ; A 0 (2) = 2; A 0 (3) = 3 28) 4 30) sin ± 1 x 2 ²± - 1 x 2 ² 40) x = ³ π 2 ´ 2 / 3 ; local max 42) (a) i (b) ii (c) iv (d) iii 48) f ( x ) = 2 x + 1 Section 5.5 2) 33 feet 6) 284 15 feet 10) displacement is 48 feet; total distance is 368 3 feet 12) displacement is 0 meters; total distance is 8 meters Section 5.6 8) 2 3 ( x 2 + 1) 3 / 2 + C 10) ( x + 1) 11 11 - ( x + 1) 10 10 + C 14) -
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Unformatted text preview: 1 64(8 x + 5) + 5 128(8 x + 5) 2 + C 16) 1 40 (4 x-1) 5 / 2 + 1 24 (4 x-1) 3 / 2 + C 20) tan 2 x 2 + C 24) e tan θ + C 28) (tan-1 x ) 3 3 + C 56) tan 5 x 5 + C 58)-1 6 (cos (4 x + 1)) 3 / 2 + C 60) 2 sin √ x + C 68) 2 √ ln x + C 82) 98 3 86) ln 2 2 94) [ f ( x )] 4 4 + C Section 5.7 4) 1 3 (ln 16-ln 10) 6) ln 2...
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This note was uploaded on 04/19/2011 for the course MATH 1042 taught by Professor Dr.z during the Spring '08 term at Temple.

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