{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

millikan

# millikan - Calculating the charge of an electron from...

This preview shows pages 1–2. Sign up to view the full content.

Calculating the charge of an electron from Millikan oil drop experiment: The idea is that each charged particle (observed in the experiment) is made up of a number of electrons and so the total charge of that particle must be a whole number multiple of the electron charge. Suppose that we have a unit for measuring electron charge that gives a value of -1 for the charge on each electron. Then all particles that we would observe in Millikan’s experiment would be whole number multiples of this value. If for example, the charged particle contained 5 electrons, then the charge on that particle would be -5. If it contained 8 electrons, then the total charge of that particle would be -8. But notice that we can never have a particle with a charge of -7.5 for example since that would require 7.5 electrons .... and we can not have partial electrons. Now the same case exists in reality with the charge of - 1 . 60 × 10 - 19 C for each electron. If we have 2 electrons in our particle, then we have a total charge of - 3 . 2 × 10 - 19 C. If we have 5 electrons in our particle, then

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern