A2s - Assignment 2 Solutions 1a EP = 10.0 m FL EP = 0 m Datum EP = 7.14 m EP = 4.28 m EP = 1.43 EP = 8.57 m EP = 5.71 m FL EP = 2.85 m Nf = 3 Ne =

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Assignment 2 Solutions 1a) N f = 3 N e = 7 H t = 10 m k = 6.0 × 10 -4 m/s k H N N Q t e f = 2.6 × 10 -3 m 3 /s/m EP = 10.0 m EP = 0 m EP = 8.57 m EP = 7.14 m EP = 4.28 m EP = 2.85 m EP = 5.71 m EP = 1.43 FL FL Datum CIVE 416: Geotechnical Engineering Winter, 2009
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1b) N f = 4 N e = 12 H t = 10 m k = 6.0 × 10 -4 m/s k H N N Q t e f = 2.0 × 10 -3 m 3 /s/m 1c) Using the element in the flownet located at the toe of the dam with flow leaving the soil: avg t a L H i Δ Δ = = 0.38 m/m avg t b L H i Δ Δ = = 0.27 m/m The hydraulic gradient in part ‘a’ ( i a ) is greater than that in part ‘b’ ( i b ). EP = 10.0 m EP = 10.0 m EP = 0 m EP = 9.17 m EP = 8.33 m EP = 0.83 m FL FL FL FL FL FL Datum CIVE 416: Geotechnical Engineering Winter, 2009
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2) N f = 5 × 2 = 10; symmetry N e = 5 H t = 2.00 – 0.83 = 1.17 m k = 5 × 10 -5 m/s k H N N Q t e f = 1.2 × 10 -4 m 3 /s/m EP = 0.83 m EP = 2.00 m FL EP = 1.77 m EP = 1.53 m EP = 1.30 m EP = 1.07 m Datum CIVE 416: Geotechnical Engineering Winter, 2009
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This note was uploaded on 04/19/2011 for the course CIVE 416 taught by Professor Meguid during the Winter '10 term at McGill.

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A2s - Assignment 2 Solutions 1a EP = 10.0 m FL EP = 0 m Datum EP = 7.14 m EP = 4.28 m EP = 1.43 EP = 8.57 m EP = 5.71 m FL EP = 2.85 m Nf = 3 Ne =

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