Marketing assignment 3

Marketing assignment 3 - Akilah Young 4/7/11 Marketing 3511...

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Akilah Young 4/7/11 Marketing 3511 Assignment 3 1a. State the null and alternate hypotheses in plain English sentences. In this case a null hypothesis would state that there is no relationship between the publication and frequency of preference. A null hypothesis for this situation would agree with management and conclude that there are no differences in the preferences for the four types of books. The alternate hypothesis would be the opposite and state that there is a relationship between teenagers and the books that were chosen. 1b. What is the calculated chi-squared value? Show your calculations. The calculated chi-squared value is 62.5. Calculated Chi-Squared Value 1B. Total= 1600 Expected Value=400 2 2 2 2 (300-400) (500-400) (450-400) (300-400) ____________ + ___________ + ____________ + _____________ = chi-squared value 400 400 400 400 6.25 + 25 + 6.25 + 25 = 62.5
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1c. The tabled chi-squared value for 5% significance and three degrees of freedom is 7.81. Can you reject the null hypothesis? Why or why not? Chi-squared value allows you to test if there really is a difference between the preferences of books. The chi- squared value is greater than the suggested table value, which is 7.81. This means that we should reject the null hypothesis. You reject it because the given data proves that there is indeed a significant difference between the preferences of books. The differences here are not just a small error. 2a. State the null and alternate hypotheses in plain English sentences . The null hypothesis for this case would state that any change in numbers between wheel alignment in Cleveland & oil change in Detroit would be because of an
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This note was uploaded on 04/19/2011 for the course MKTG 3511 taught by Professor Atwater during the Spring '08 term at Temple.

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Marketing assignment 3 - Akilah Young 4/7/11 Marketing 3511...

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