Week 3 Assignment

Week 3 Assignment - Week3Assignment Section2.4: 2.

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Week 3 Assignment Section 2.4: 2. Solve i = Prt for i, given that P = $5000, r = 6%, and t = 3.5 years. i = Prt i = 5000(6%)(3.5) i = 5000(0.06)(3.5) 1050 = 5000(0.06)(3.5) i = 1050 The interest is $1050 4. Solve i = Prt for t, given that P = $1250, r = 3%, and i = $150. i = Prt 150 = 1250(3%)t 150 = 1250(0.03)t 150 = 37.5t 150  = 4 37.5 150 = 1250(0.03)(4) 4 = t The time is 4 years. 8. Solve i = Prt for P, given that r = 8.5%, t = 2 years, and i = $204. i = Prt 204 = P(8.5%)(2) 204 = P(0.085)(2) 204 = P(0.17) 0.17  = 1200 204 204 = 1200(0.085)(2)
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1200 = P The principal is $1200. 10. Solve A = P + Prt for A, given that P = $850, r = 4.5%, and t = 10 years. A = P + Prt A = 850 + 850(4.5%)(10) A = 850 + 850(0.045)(10) A = 850 + 382.5 1232 = 850 + 850(0.045)(10) A = 1232.5 The amount is $1232.50 12. Solve A = P + Prt for r, given that A = $516, P = $300, and t = 8 years.  Express r as  a percent. A = P + Prt 516 = 300 + 300(r)(8) 516 = 300 + 2400r 516 = - 300 + 300 + 2400r 216 = 2400r 216  = 0.09 2400r 516 = 300 + 300(0.09)(8) 0.09 = r 9% = r The rate is 9%. 14. Solve A = P + Prt for P, given that A = $720, r = 8%, and t = 10 years. A = P + Prt 720 = P + P(8%)(10) 720 = P + P(0.08)(10) 720 = P + 0.8P 720 = P + 1.8P  720  = 400
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1.8P 720 = 400 + 400(0.08)(10) 400 = P The principal is $400. 17. Solve V = Bh for h.  (Volume of a prism) V = Bh for h 1  (V) = 1  (Bh) B  B V = (B) (V )    B V  = h B 18. Solve A = lw for l.  (Area of a Rectangle) A = lw for l 1  (A) = 1  (lw) l   l A = (A ) (w)          w A  = l w 20. Solve V =  1  Bh for B.  (Volume of a pyramid)        3 V = 1  Bh for b                    3 1  (Bh) (3) = 3v    (1/3 gets cancelled out) 3          bh
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3v  ÷ h = (3v ) = B bh      h V = 1  (3v ) (h)        3  h 3v  = B  h 21. Solve C = 2 r for r.  (Circumference of a circle) π C = 2 r for r π 1  (C) = 1  (2 r) π 2  2 C = 2  ( π C ) 2 r π  C  = r 2 r π 22. Solve A = 2 r π + 2 rh for h.  (Surface area of a circular cylinder) π A = 2 r π 2 2 rh = 2 r π π 2 h = 2 r π     2          2 r π A = 2 r π + 2 rh π A - 2 r π = 2 rh π A - 2 r π = (2 r)h π  A 2 r - r = h π
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A - 2 r π     2     = h     2 r π 23. Solve I = 100M  for C.  (Intelligence quotient)                     C I = 100M  for C           C C(I) = C (100M )         C C I = 100M 1  (C I) = 1  (100M) I    I I = 100M  =  C = 100M           I                     C C = 100M I 24. Solve A = 1 h(b
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Week 3 Assignment - Week3Assignment Section2.4: 2.

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