CH101-Assignment 17

CH101-Assignment 17 - products for the following reaction:...

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1. Please input numbers (not words) in the boxes. Positive numbers are accepted with or without the "+" sign. (a) What is E of the reaction A B? 10kJ/mol (b) Is it an endothermic or an exothermic reaction? endothermic exothermic (c) What is the activation energy for the forward reaction (A B)? 20kJ/mol (d) What is the activation energy for the reverse reaction (B A)? 10kJ/mol (e) Given equal concentrations of A and B, which reaction has the greater rate, A B or B A? B A A B 2. Consider the following reaction: CH 3 OH + Cl 1- OH 1- + CH 3 Cl a) Based on the bond energies given in Table 9.2 on page 189 of the textbook, or the Bond Energy Resource in the on-line text, which side has the lower energy in the reaction energy diagram for this reaction? reactant side product side
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b) Based on the energy diagram you would draw for this equilibrium, which reaction has the greater activation energy? reverse forward c) The value of Gº for this reaction will most likely be: positive negative 3. Identify the equilibrium constant expression in terms of the concentrations of the reactants and
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Unformatted text preview: products for the following reaction: 2HNO 2 (aq) + PO 4 3-(aq) 2NO 2 1-(aq) + H 2 PO 4 1-(aq) K = (2[HNO 2 ] + [PO 4 3-]) / (2[NO 2 1-] + [H 2 PO 4 1-]) K = (2[HNO 2 ] [PO 4 3-]) / (2[NO 2 1-] [H 2 PO 4 1-]) K = ([NO 2 1-] 2 [H 2 PO 4 1-]) / ([HNO 2 ] 2 [PO 4 3-]) K = ([HNO 2 ] 2 + [PO 4 3-]) / ([NO 2 1-] 2 + [H 2 PO 4 1-]) K = (2[NO 2 1-] [H 2 PO 4 1-]) / (2[HNO 2 ] [PO 4 3-]) K = ([HNO 2 ] 2 [PO 4 3-]) / ([NO 2 1-] 2 [H 2 PO 4 1-]) K = ([NO 2 1-] 2 + [H 2 PO 4 1-]) / ([HNO 2 ] 2 + [PO 4 3-]) 4. Identify the equilibrium constant expression in terms of the concentrations of the reactants and products for the following reaction: 3Fe(s) + 2Au 3+ (aq) 2Au(s) + 3Fe 2+ (aq) K = ([Au] 2 + [Fe 2+ ] 3 ) / ([Fe] 3 + [Au 3+ ] 2 ) K = [Fe 2+ ] 3 / [Au 3+ ] 2 K = [Au 3+ ] 2 / [Fe 2+ ] 3 K = (2[Au] + 3[Fe 2+ ]) / (3[Fe] + 2[Au 3+ ]) K = (2[Au] 3[Fe 2+ ]) / (3[Fe] 2[Au 3+ ]) K = ([Au] 2 [Fe 2+ ] 3 ) / ([Fe] 3 [Au 3+ ] 2 )...
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CH101-Assignment 17 - products for the following reaction:...

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