20105ee211A_1_HW5Solutions

20105ee211A_1_HW5Solutions - 1 EE 211A Digital Image...

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Unformatted text preview: 1 EE 211A Digital Image Processing I Fall Quarter, 2010 Handout 18 Instructor: John Villasenor Homework 5 Solutions Solutions: 1. a. ( 29 ( 29 1 * 2 2 1 1 2 1 2 1 2 M T u k k k R u u M- = - = =- +- - . 2 1 1 1 4 -- = b. | | I R u - , 266 . 4 1 2 9 2 = +- = = 0.234. To find , = +-- = -- C C C C 266 . 4 266 . 4 2 1 4 1 2 1 1 1 4 - = 266 . C normalized - = 257 . 966 . = 966 . 257 . 1 c. . 966 . 257 . 257 . 966 . * 1 * * - = = T T T d. . 514 . 932 . 1 452 . 189 . 2 1 * 1 * -- = = - = = u v u v T T . 1 2 966 . 257 . 452 . 257 . 966 . 189 . 2 ) 1 ( ) ( 1 u v v = - = - - = + e. v R = ] [ 2 1 * 1 1 * T T v v v v + 2 = = + -- 234 . 26 . 4 264 . 99 . 99 . 73 . 3 204 . 989 . 989 . 79 . 4 2 1 = diag ) ( k ....
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20105ee211A_1_HW5Solutions - 1 EE 211A Digital Image...

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