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20105ee211A_1_HW6Solutions

# 20105ee211A_1_HW6Solutions - EE 211A Fall Quarter 2010...

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EE 211A Digital Image Processing I Fall Quarter, 2010 Handout 20 Instructor: John Villasenor Homework 6 Solutions Solutions: 1. a) 5 4 4 5 T UU = , 1/ 2 3 0 0 1 Λ = , 0 1 0.7071 0.7071 , 0.7071 0.7071 ψ = ± = ± - 5 4 4 5 T U U - = - , 1/ 2 3 0 0 1 Λ = , 0 1 0.7071 0.7071 , 0.7071 0.7071 φ = ± = ± - 2 1 0.7071 0.7071 3 0 0.7071 0.7071 1 2 0.7071 0.7071 0 1 0.7071 0.7071 T U - -     = = = ΨΛΦ     - -     b) [ ] 0 0 0.7071 1 1 1 0.7071 0.7071 0.7071 1 1 2 T ψ φ - = - = - [ ] 1 1 0.7071 1 1 1 0.7071 0.7071 0.7071 1 1 2 T = = - - - We can verify the answer as follow: 0 0 0 1 1 1 1 1 1 1 2 1 3 1 1 1 1 1 1 2 2 2 T T U λ ψ φ λψ φ - - = + = + =

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20105ee211A_1_HW6Solutions - EE 211A Fall Quarter 2010...

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