umn EE 3005 (Imbertson) Exam 1, Spring 2011

umn EE 3005 (Imbertson) Exam 1, Spring 2011 - NAME_Solution...

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Unformatted text preview: NAME_____Solution_____________________________ ID #____________________________________ EE 3005 Spring 2011 Midterm 1 closed book closed notes calculator permitted Q #1 (25 pts) Fill in the Blanks a) Find the current through each element and the voltage across each element in the circuit diagrammed below. (Mark the values right on the schematic and be sure to include polarities.) b) Find the power (P) of the box element. Indicate whether the power is absorbed or delivered. 40 3A (delivering 720 W) 240 P = ________? Solution: Q #2 (25 pts) Thevenin Find the Thevenin equivalent as seen at nodes A and B. Draw the schematic of the Thevenin equivalent including component values. 2 A 10 V 2 4 2 B Solution: Use voltage divider Q #3 (25 pts) Use superposition to find vA. Superposition Solution: With only the 30 volt source energized: With only the 15 volt source energized: With only the 3 amp source energized: So, with all sources energized: VA = 10 volts VA = -10 volts VA = -10 volts VA = 10 – 10 – 10 = -10 volts 3A 10 10 ++ v 15 V 30 V + _ 10 Q #4 (25 pts) Nodal Analysis Use nodal analysis to find v1, v2, and v3. 20 V +v3 2 - v + v1 +5V v2 12.5 A 0.5 0.25 v 1 30 V + _ 4 Solution: KCL at v1, v2,v3 supernode: Supernode relation equations: By substitution: ...
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This note was uploaded on 04/20/2011 for the course EE 3005 taught by Professor Tedk.higman during the Spring '08 term at Minnesota.

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