EGR 201 2.91

# EGR 201 2.91 - -87.9385>> i=Px Qx i = 174.3659>>...

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Matt Richards EGR 201-61 Assignment 2.91 4/21/2011 Problem 91, pg 56 Page 1 of 2 Given: P= 300N Q= 400N Find: Find the magnitude and resultants of the two forces Plan: Rectangular components >> P=300 P = 300 >> Q=400 Q = 400 >> Py=P*cosd(60) Py = 150.0000 >> Px=- P*(sind(60))*(sind(15)) Px = -67.2432 >> Pz=P*(sind(60))*(cosd(15)) Pz = 250.9549 >> Qy=Q*cosd(40) Qy = 306.4178 >> Qx=Q*(sind(40))*(cosd(20)) Qx = 241.6091 >> Qz=-Q*(sind(40))*(sind(20)) Qz =

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Unformatted text preview: -87.9385 >> i=Px+Qx i = 174.3659 >> j=Py+Qy j = 456.4178 >> k=Pz+Qz k = 163.0164 >> R=sqrt(i^2+j^2+k^2) R = 515.0680 >> ThetaX=Acosd(i/R) Matt Richards EGR 201-61 Assignment 2.91 4/21/2011 Problem 91, pg 56 Page 2 of 2 ThetaX = 70.2127 >> ThetaY=acosd(j/R) ThetaY = 27.6090 >> ThetaZ=acosd(k/R) ThetaZ = 71.5489 Summary: R=515.0680N ThetaX=70.2127° ThetaY=27.6090° ThetaZ=71.5489°...
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EGR 201 2.91 - -87.9385>> i=Px Qx i = 174.3659>>...

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