EGR 201 2.123 - -.86/1.86 .181AB-.215TAE=0...

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Matt Richards EGR 201-61 Assignment 2.123 4/21/2011 Problem 123, pg 63 Page 1 of 2 Given: W=1000N Find: Determine the magnitude of P Plan: Using three dimensional equilibrium/sum of forces=0 i j k AB -.78/1.78 1.6/1.78 0 AC 0 1.6/2 1.2/2 AD 1.3/2.1 1.6/2.1 .4/2.7 AE -.4/1.86 1.6/1.86
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Unformatted text preview: -.86/1.86 .181AB-.215TAE=0 1.661AB+.8AC+.86AE-1000=0 .19AB+.16AC-.462AE=0 P=AB AB=377.32 AC=125.1 AE=317.65 Matt Richards EGR 201-61 Assignment 2.123 4/21/2011 Problem 123, pg 63 Page 2 of 2 Summary: P=377.32N...
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EGR 201 2.123 - -.86/1.86 .181AB-.215TAE=0...

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