MATH 117 Week 4 Concept Check

# MATH 117 Week 4 Concept Check - as 1=2 or make the...

This preview shows pages 1–2. Sign up to view the full content.

When solving a rational equation, why is it necessary to perform a check? It is always good to check a solution to make sure you made no mistakes. But now, in some cases, you may get an answer which when plugged in does not work, even though you did every step right. These extraneous solutions are solutions that are obtained through algebra but are not “real solutions”. So it’s important to perform a check so we can check the validity of the solution, and keep it if it works and discard if not. What happens is that the solutions when plugged back in either pose impossibilities such

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: as 1=2 or make the denominator zero in a term. Here is an example:-- -= x 2x 6 4x 24x2 6x- = xx 2xx 6 4x 6xx 6 24x2 6x x2 2xxx 6 4x 24xx 6 24x2 6x + x2 6x 24x2 6x 24x2 6x x2 6x 24 24 x2 6x 0 = , x 6 0 CHECK- ( ) 6 26 6 46 2462 6 6 undef 23 undef ! 6 is not a solution CHECK 0 20 6 40 2402 6 0 13 undef undef ! 0 is not a solution , Both values when plugged in make the denom zero thus there is no solution the original solutions are extraneous...
View Full Document

## This note was uploaded on 04/20/2011 for the course MATH 116 taught by Professor Mcmillian during the Spring '09 term at University of Phoenix.

### Page1 / 2

MATH 117 Week 4 Concept Check - as 1=2 or make the...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online