Week 3 DQ 9 - into a quadronimial by slicing the bx term...

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Please post a 150-300-word response to the following discussion question by clicking on Reply . Why is (3x + 5) (x - 2) + (2x - 3) (x - 2) not in factored form? What is the correct final factored form? What is this factoring method called? ______________________________________________________________ This is not fully factored since in this whole binomial, each term in the binomial has a factor which can be taken out (GCF of the whole big binomial). That factor is (x-2). When that is took out, this is what is left: (3x + 5) (x - 2) + (2x - 3) (x - 2) =[(3x + 5) (x - 2) + (2x - 3) (x - 2)] =(x-2)[(3x+5)+(2x-3)] =(x-2)[3x+5+2x-3] =(x-2)(5x+2) This style of factoring is called grouping factoring, where you split the trinomial
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Unformatted text preview: into a quadronimial by slicing the bx term into two parts so the two slices have coefficients which add up to b and multiplies out to "a times c". After this, the first 2 terms are grouped, and so are the last two. Factor the two groups my removing the GCFs. If the trinomial is factorable, then in each group when factored must have a matching term in paranthesis as in the example above shows. Then that is factors out of the whole entire binomial and the final factored form is found. This style is good to use when the leading coefficient is not 1 or -1. If it is 1 or -1, then just do the factoring the normal way....
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This note was uploaded on 04/20/2011 for the course MATH 116 taught by Professor Mcmillian during the Spring '09 term at University of Phoenix.

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