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CHEM 120 Practice Midterm 2010

CHEM 120 Practice Midterm 2010 - Practice Midterm 1...

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Practice Midterm 1 CHEMISTRY 120 GENERAL CHEMISTRY Examiners: Prof. B. Siwick Name:_________________________ Prof. A. Mittermaier Prof. A. Fenster INSTRUCTIONS (for the actual Midterm) 1. Enter your student number and name on the computer scorecard provided, by filling in the appropriate circles. Check that your scorecard has the correct version number filled in ( version 1 ). If not, fill that in. 2. This examination comprises 30 questions (14 pages including cover page and 4 blank pages). All questions are of equal value. 3. Transfer answers to the scantron computer scorecard provided. 4. Both the scorecard and the examination paper will be collected separately at the end of the examination period. 5. Simple Calculators are allowed, and translation dictionaries. NO notes or texts are allowed. 6. The Examination Security Monitor Program detects pairs of students with unusually similar answer patterns on multiple-choice exams. Data generated by this program can be used as admissible evidence, either to initiate or corroborate an investigation or a charge of cheating under Section 16 of the Code of Student Conduct and Disciplinary Procedures. NOTE TO INVIGILATORS: At the end of the exam, both scorecards and exam papers should be collected. Collect scorecards separately.
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THESE DATA WILL BE PROVIDED ON THE MIDTERM EXAMINATION STP: 0°C and 1 atm 1 mol gas at STP: 22.4 L k = 1.38 x 10 –23 J/K 0 K = – 273.15 °C e = 2.718 1 Pa = 1 N/m 2 g = 9.81 m/s 2 1 atm = 101.3 kPa = 760 Torr π = 3.14 1 bar = 100,000 Pa = 100 kPa R = 8.314 J/(mol K) 1 J = 1 kg m 2 /s 2 = 1 kPa L = 0.08206 L atm /(mol K) 1 mol = 6.02 x 10 23 molecules nRT PV = 2 2 2 2 1 1 1 1 T n V P T n V P = RT MP d = RT MPV m = 2 3 1 u m V N P = A k N RT e 2 3 = M RT u rms 3 = hdg P = Integrated Rate Laws: Arrhenius Equation: Order 0: [A] = [A] 0 - k t / a E RT k Ae = Order 1: [A] = [A] 0 e - k t 2 1 2 1 1 1 ln a E k k R T T = Order 2: 1/[A] = 1/[A] 0 + kt
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Standard states for various elements under STP conditions: Hydrogen: H 2 (g) Carbon: C(s, graphite) Nitrogen: N 2 (g) Oxygen: O 2 (g) Copper: Cu(s) Sulphur: S(s)
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1) Calculate the height in meters of a column of liquid glycerol (density = 1.26 g/cm 3 ) required to exert the same pressure as 760 mmHg (d = 13.60 g/cm 3 ). a) 8.20 m b) 8.20 × 10 3 m c) 0.704 m d) 44.4 m e) 70.4 m
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