This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: moore (jwm2685) – HW09 – gilbert – (55485) 1 This printout should have 19 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. 001 10.0 points Which of the following statements are true for all lines and planes in 3space? I. two lines parallel to a third line are par allel , II. two planes parallel to a third plane are parallel , III. two lines perpendicular to a plane are parallel . 1. I and II only 2. II only 3. all of them correct 4. III only 5. none of them 6. I and III only 7. II and III only 8. I only Explanation: I. TRUE: each of the two lines has a direc tion vector parallel to the direction vector of the third line, so must be scalar multiples of each other. II. TRUE: each of the two planes has a normal vector parallel to the normal vector of the third plane, and so are parallel, hence the planes are parallel. III. TRUE: the two lines will have direction vectors parallel to the normal vector of the plane, and so be parallel, hence the two lines are parallel. 002 10.0 points Which of the following surfaces is the graph of 6 x + 4 y + 3 z = 12 in the first octant? 1. x y z 2. x y z correct 3. x y z moore (jwm2685) – HW09 – gilbert – (55485) 2 4. x y z 5. x y z 6. x y z Explanation: Since the equation is linear, it’s graph will be a plane. To determine which plane, we have only to compute the intercepts of 6 x + 4 y + 3 z = 12 . Now the xintercept occurs at y = z = 0, i.e. at x = 2; similarly, the yintercept is at y = 3, while the zintercept is at z = 4. By inspection, therefore, the graph is x y z 003 10.0 points Find parametric equations for the line pass ing through the point P (2 , − 3 , 4) and parallel to the vector ( 4 , 1 , − 4 ) . 1. x = 4 + 2 t, y = 1 − 3 t, z = − 4 + 4 t 2. x = 2 + 4 t, y = − 3 + t, z = 4 − 4 t correct 3. x = 4 − 2 t, y = − 1 + 3 t, z = − 4 + 4 t 4. x = 4 + 2 t, y = 1 + 3 t, z = 4 − 4 t 5. x = 2 − 4 t, y = 3 − t, z = 4 − 4 t 6. x = − 2 + 4 t, y = 3 + t, z = − 4 − 4 t Explanation: A line passing through a point P ( a, b, c ) and having direction vector v is given para metrically by r ( t ) = a + t v , a = ( a, b, c ) . Now for the given line, a = ( 2 , − 3 , 4 ) , v = ( 4 , 1 , − 4 ) . Thus r ( t ) = ( 2 + 4 t, − 3 + t, 4 − 4 t ) . Consequently, x = 2 + 4 t, y = − 3 + t, z = 4 − 4 t are parametric equations for the line. keywords: line, parametric equations, direc tion vector, point on line 004 10.0 points moore (jwm2685) – HW09 – gilbert – (55485) 3 A line ℓ passes through the point P (3 , 2 , 1) and is perpendicular to the plane x + 3 y + z = 6 . At what point Q does ℓ intersect the xy plane?...
View
Full
Document
This note was uploaded on 04/21/2011 for the course M 408 D taught by Professor Textbookanswers during the Spring '07 term at University of Texas.
 Spring '07
 TextbookAnswers

Click to edit the document details