chapter17_ls - select C (lowest cost on critical path) and...

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Lecture Suggestions - Chapter 17 Example 7: Time-Cost Tradeoffs: Crashing 1. Select the Example 7 worksheet 2. End, and Normal time. 3. 4. and activities c, d, e, and f are on the critical path (indicated by red). 5. Crashing Cost =300. 6 a total crash cost = 300. Repeat steps 5 and 6: 7. Crashing Cost =600. 8. a total crash cost = 900. Repeat steps 5 and 6: 7. Crashing Cost =800. 8. a total crash cost = 1700. 9. (Optional) Clear worksheet (press Clear and confirm with OK) and re-enter data for Activity, Start, If you did not Clear all data, clear Crashing Time and Cost columns (select and press delete). Press the Solve button , the resulting solution shows that the project can be completed in 20 days Select job to be crashed:
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Unformatted text preview: select C (lowest cost on critical path) and enter Crashing Time = 1 and Press Solve button , the resulting solution shows that the project cam be completed in 19 days with Select job to be crashed: select E (lowest cost on critical path) and enter Crashing Time = 1 and Press Solve button , the resulting solution shows that the project cam be completed in 18 days with Select job to be crashed: select F (lowest cost on critical path) and enter Crashing Time = 1 and Press Solve button , the resulting solution shows that the project cam be completed in 17 days with At this point all activities are on the critical path (indicated in red) and no further crashing is possible ....
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This note was uploaded on 04/21/2011 for the course MGT 02 taught by Professor Gad during the Spring '11 term at Tanta University.

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