HW 14 solution

HW 14 solution - song (shs546) Homework 14 weathers (22202)...

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Unformatted text preview: song (shs546) Homework 14 weathers (22202) 1 This print-out should have 15 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 4) 10.0 points Four long, parallel conductors carry equal cur- rents. A cross-sectional view of the conduc- tors is shown in the figure. Each side of the square has length of 0 . 9 m. The current direc- tion is out of the page at points indicated by the dots and into the page at points indicated by the crosses. A B C D P x y . 9 m 2 A 2 A 2 A 2 A Which diagram correctly denotes the di- rections of the components of the mag- netic field from each conductor at the point P ? The permeability of free space is 1 . 25664 10 6 N / A 2 . 1. P B A B B B C B D 2. P B A B B B C B D 3. P B A B B B C B D correct 4. P B A B B B C B D 5. P B A B B B C B D 6. P B A B B B C B D Explanation: Let : I = 2 A and = 0 . 9 m . The directions of the magnetic field due to each wire are given by the right hand rule, where the thumb points in the direction of the current and your fingers curl in the direction of the magnetic fields circular path. Consider the magnetic field contributions due to the currents in A and B only: song (shs546) Homework 14 weathers (22202) 2 A B P 2 A in 2 A out B A B B Consider the magnetic field contributions due to the currents in C and D only: C D P 2 A in 2 A in B C B D Consider the results of all four magnetic field contributions superimposed on one an- other: A B C D P . 9 m 2 A in 2 A out 2 A in 2 A in B A B B B C B D 002 (part 2 of 4) 10.0 points What is the magnitude of each of the four components B A , B B , B C , and B D at the point P? 1. bardbl vector B A,B,C, or D bardbl = I 2 2 2. bardbl vector B A,B,C, or D bardbl = I 2 3. bardbl vector B A,B,C, or D bardbl = I 2 correct 4. bardbl vector B A,B,C, or D bardbl = I 2 5. bardbl vector B A,B,C, or D bardbl = I 2 2 Explanation: By Amperes law, the line integral around any closed path is equal to I . Here the path is defined by the circle with radius r . contintegraldisplay vector B dvectors = I B 2 r = I B = I 2 r , where r = cos 45 = 2 is the distance from any of the wires to P, from which it follows that B A = B B = B C = B D . B A = I 2 . 003 (part 3 of 4) 10.0 points What is the magnitude of the magnetic field at point P ? 1. vextenddouble vextenddouble vextenddouble vector B net vextenddouble vextenddouble vextenddouble = (1 . 41421) vextenddouble vextenddouble vextenddouble vector B A,B,C, or D vextenddouble vextenddouble vextenddouble 2....
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This note was uploaded on 04/22/2011 for the course PHYS 2220 taught by Professor Littler during the Spring '00 term at North Texas.

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HW 14 solution - song (shs546) Homework 14 weathers (22202)...

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