HW 15 solution

HW 15 solution - song (shs546) Homework 15 weathers (22202)...

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Unformatted text preview: song (shs546) Homework 15 weathers (22202) 1 This print-out should have 12 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points A wire in the shape of an equilateral trian- gle 5 . 49 cm on a side is placed in a uniform magnetic field of magnitude 0 . 0613 T. If the field makes an angle of 19 . 8 with the plane of the triangle, determine the magnetic flux through the triangle. Correct answer: 2 . 71 10 5 T m 2 . Explanation: The angle vector A makes with vector B is = 90 19 . 8 = 70 . 2 . The magnetic flux through the triangle equals, = B A cos = (0 . 0613 T) A cos 70 . 2 , where A is the area of the triangle. In an equilateral triangle, all angles are 60 . Thus, the height of the triangle is h = (5 . 49 cm) sin(60 ) = 4 . 75448 cm , and the area of the triangle is A = 1 2 (5 . 49 cm)(4 . 75448 cm) = 13 . 051 cm 2 = 0 . 0013051 m 2 . Therefore, = (0 . 0613 T) (0 . 0013051 m 2 ) cos 70 . 2 = 2 . 71 10 5 T m 2 . 002 10.0 points Gauss law for magnetism tells us 1. the magnetic field of a current element. 2. that the magnetic monopoles do not exist. correct 3. the net charge in any given volume. 4. that charges must be moving to produce magnetic fields. 5. that the line integral of a magnetic field around any closed loop vanishes. Explanation: 003 10.0 points A magnetic field B is applied to a param- agnet at room temperature. In the interior, the field produced by the magnetic dipoles of this substance is 1. greater than B and in the same direc- tion. 2. less than B and in the same direction. correct 3. less than B and in the opposite direc- tion. 4. the same as B . 5. greater than B and in the opposite di- rection. Explanation: Because is much smaller than 1, the ratio of total magnetization, or the magnetic dipole moment per unit volume, to the applied field is less than 1. 004 10.0 points Given: A loop with current I produces a magnetic moment , as shown below. Consider the following four configurations of two loops each, A , B , C , and D . The placement and current directions of the loops are shown below. The loops are characterized song (shs546) Homework 15 weathers (22202) 2 by their magnetic moments ....
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HW 15 solution - song (shs546) Homework 15 weathers (22202)...

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