Lec25V

# Lec25V - Lecture 25-1 Lecture Locating Images only using...

This preview shows pages 1–6. Sign up to view the full content.

Lecture 25 Lecture 25 -1 Locating Images Real images form on the side of a mirror where the objects are, and virtual images form on the opposite side. only using the parallel, focal, and/or radial rays.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Lecture 25 Lecture 25 -2 Mirror Equation and Magnification '' ys m == ' s m s ≡− s is positive if the object is in front of the mirror (real object) s is negative if it is in back of the mirror (virtual object) s’ is positive if the image is in front of the mirror (real image) s’ is negative if it is in back of the mirror (virtual image) m is positive if image and object have the same orientation (upright) m is negative if they have opposite orientation (inverted) f and r are positive if center of curvature in front of mirror (concave) f and r are negative if it is in back of the mirror (convex) 11 1 ' s sf += ( f = r/2 )
Lecture 25 Lecture 25 -3 DOCCAM 2 7A-10 F and 2F Mirror

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Lecture 25 Lecture 25 -4 READING QUIZ 1 Which of the following statements is incorrect ? The statements describe the optical characteristics of the human eye. A| A near sighted eye focuses in front of the retina when observing an object located at infinity. B| A far sighted eye focuses behind the retina when observing an object located at infinity. C| A converging lens is used to correct the vision of a near sighted eye. D| Astigmatism is a condition where the eye does not have cylindrical symmetry about the central optical axis. E| A cataract operation of the second lens inside the eye removes the clouded lens and replaces it with a plastic implant.
Lecture 25 Lecture 25 -5 s S’ Refracting Surface Formula 11 2 2 2 2 sin sin nn θ θθ = ∴≈ 12 2 1 , () n n αβ βθ γ α γβ = += + ∴+ =− A point object O is placed on the central axis of a convex refracting surface. The center of curvature of the surface is at C . It is easy to see (for small angles) Derivation: 2 1 , ' , ' ac ac ac n sr n ss r s αβγ + = = ≈≈ ) )) But Setting for parallel rays, the focal length is s =∞ 2 21 n f r = f (and r)>0 for convex surface, f (and r)<0 for concave surface, for n 2 > n 1 , where light goes 1-->2 Parallel ray refracts through the focal point. A ray through the focal point refracts parallel to the central axis.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 25

Lec25V - Lecture 25-1 Lecture Locating Images only using...

This preview shows document pages 1 - 6. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online