ENGR 132 - QUIZ18

# ENGR 132 - QUIZ18 - how much time the speed is over 2 m s...

This preview shows pages 1–6. Sign up to view the full content.

Click to edit Master subtitle style 4/24/11 ENGR 132 Wed/Fri 3:30-5:30

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
4/24/11 Quiz 18 Write the code required to find the first peak on the plot below. t e t t t f 3 5 23 3 - + - = ) cos( ) ( 0 1 2 3 4 5 -1 -0.5 0 0.5 1 1.5 2 2.5 3 3.5 Time (s) Velocity (m/s)
4/24/11 Solution - Quiz 18 Notes: Need to use x as independent variable (no t’s!!) Need to flip the function (define y_neg) y='2+cos(5*x)*(x^2- 3)/exp(x)' y_neg=['-(' y ')'] xmin=fminbnd(y_neg,0,1) x=xmin y_min=eval(y) +2 +2 +2 +2 +2

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Click to edit Master subtitle style 4/24/11 ENGR 132 Tues/Thurs 9:30-11:30

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: how much time the speed is over 2 m/ s on the interval [0,1] t e t t t f 3 5 23 3-+-= ) cos( ) ( 1 2 3 4 5-1-0.5 0.5 1 1.5 2 2.5 3 3.5 Time (s) Velocity (m/s) 4/24/11 Solution - Quiz 18 Notes: Must subtract 2 from the original eqn Must have good initial guess for each zero y=‘-25+cos(5*x)*(x^2-3)/exp(x)' zero_1=fzero(y,0.1) zero_2=fzero(y,0.8) time_over_2=zero_2-zero_1 +3 +2 +2 +3...
View Full Document

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern