Lecture08_Pushkar_tentative

# Lecture08_Pushkar_tentative - Lecture 8 Purdue University,...

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Unformatted text preview: Lecture 8 Purdue University, Physics 220 1 Lecture 08 Circular Motion PHYSICS 220 Lecture 8 Purdue University, Physics 220 2 Banked Curve A car drives around a curve with radius 410 m at a speed of 32 m/s. The road is banked at 5.0°. The mass of the car is 1400 kg. A) What is the frictional force on the car? B) At what speed could you drive around this curve so that the force of friction is zero? Lecture 8 Purdue University, Physics 220 3 θ = 5 r = 410 m v = 32 m / s Σ F y = ma y = N cos θ - mg- f sin θ = y-direction Σ F x = ma x = ma N sin θ + f cos θ = ma = m v 2 r x-direction θ x y N W f Banked Curve (1) (2) Lecture 8 Purdue University, Physics 220 4 f sin θ + mg cos θ sin θ + f cos θ = mv 2 r f (sin 2 θ + cos 2 θ ) = mv 2 r cos θ - mg sin θ f = m v 2 r cos θ - g sin θ = 2300 N 2 equations and 2 unknown we can solve for N in (1) and substitute in (2) N = f sin θ + m g cos θ N sin θ + f cos θ = m v 2 r Banked Curve Lecture 8 Purdue University, Physics 220 5 Banked Curve A car drives around a curve with radius 410 m at a speed of 32 m/s. The road is banked at 5.0°. The speed of 32 m/s....
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## This note was uploaded on 04/23/2011 for the course PHYS 220 taught by Professor Chang during the Spring '09 term at Purdue.

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Lecture08_Pushkar_tentative - Lecture 8 Purdue University,...

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