Lecture12_tentative

Lecture12_tentative - PHYSICS 220 Lecture 12 Collision and...

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Lecture 12 1 Lecture 12 Collision and Explosion PHYSICS 220
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Lecture 12 2 Example A freight train is being assembled in switching yard. Car 1 has a mass of m 1 =65 × 10 3 kg and moves at a velocity v 01 =0.80 m/s. Car 2 has a mass of m 2 =92 × 10 3 kg and moves at a velocity v 02 =1.3 m/s and couples to Car 1. Neglecting friction, find the common velocity v f of the cars after they become coupled. m 2 m 1 v 02 v 01 initial m 2 m 1 v f final
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Lecture 12 3 Example Apply conservation of momentum: P i =m 1 v o1 +m 2 v 02 P f =(m 1 2 )v f (m 1 2 f = m 1 v 01 2 v 02 v f = m 1 v 01 + m 2 v 02 m 1 + m 2 = (65 × 10 3 kg )(0.8 m / s ) + (92 × 10 3 kg )(1.3 m / s ) (65 × 10 3 kg + 92 × 10 3 kg ) = 1.1 m / s A fright train is being assembled in switching yard. Car 1 has a mass of m 1 =65 × 10 3 kg and moves at a velocity v 01 =0.80 m/s. Car 2 has a mass of m 2 =92 × 10 3 kg and moves at a velocity v 02 =1.3 m/s and couples to it. Neglecting friction, find the common velocity v f of the cars after they become coupled.
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Lecture 12 4 Center of Mass Center of Mass Example 1: L m m Example 2: L m 5m x CM = (0 + mL)/2m = L/2 x = (0 + 5mL)/6m = 5L/6 X=0 X=L r r cm = m 1 r r 1 + m 2 r r 2 m 1 + m 2
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Lecture 12 5 Center of Mass For symmetric objects that have uniform density the CM will simply be at the geometrical center!
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This note was uploaded on 04/23/2011 for the course PHYS 220 taught by Professor Chang during the Spring '09 term at Purdue.

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Lecture12_tentative - PHYSICS 220 Lecture 12 Collision and...

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