hw3_print

hw3_print - STAT416: Probability Spring 2011 Assignments 1...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: STAT416: Probability Spring 2011 Assignments 1 Homework #3 (Solution) February 8, 2011 1 Total possible points is 45 1. Ex. 3.2 (5 pts) . P ( Sat ) = 0 . 6, P ( Sun ) = 0 . 8, P ( Sat c Sun c ) = 0 . 1. P ( Sun | Sat ) = P ( Sun Sat ) P ( Sat ) . But P ( Sat c Sun c ) = P ([ Sun Sat ] c ) = 1- P ( Sun Sat ) = 1- [ P ( Sun ) + P ( Sat )- P ( Sun Sat )] P ( Sun Sat ) = 0 . 6 + 0 . 8- . 9 = 0 . 5. Therefore, P ( Sun | Sat ) = P ( Sun Sat ) P ( Sat ) = . 5 . 6 = 5 6 = 0 . 833 . 2. Ex. 3.6 (5 pts) . Define the events A =computer doesnt work, B =nothing interesting on TV, and C =she doesnt pick up the phone. Then, P (Sam goes to bed at 8pm) = P ( A B C ) = P ( C | A B ) P ( B | A ) P ( A ) = 0 . 1 . 3 . 75 = 0 . 0225 . 3. Ex. 3.8 (5 pts) . 3B4G5R. There is a total of 12 balls. P (both red | same color) = P ( RR ) P ( RR ) + P ( BB ) + P ( GG ) = 5 12 4 11 5 4 12 11 + 4 3 12 11 + 3 2 12 11 = 10 19...
View Full Document

Page1 / 2

hw3_print - STAT416: Probability Spring 2011 Assignments 1...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online