Chapter 1
17
a.
Number
Nonconforming
Frequency
RelativeFrequency(Freq/60)
0
7
0.117
1
12
0.200
2
13
0.217
3
14
0.233
4
6
0.100
5
3
0.050
6
3
0.050
7
1
0.017
8
1
0.017
doesn't add exactly to 1 because relative frequencies have been rounded
1.001
b.
The number of batches with at most 5 nonconforming items is 7+12+13+14+6+3 = 55, which is a
proportion of 55/60 = .917.
The proportion of batches with (strictly) fewer than 5 nonconforming
items is 52/60 = .867.
Notice that these proportions could also have been computed by using the
relative frequencies: e.g., proportion of batches with 5 or fewer nonconforming items = 1
(.05+.017+.017) = .916; proportion of batches with fewer than 5 nonconforming items = 1 
(.05+.05+.017+.017) = .866.
c.
The center of the histogram is somewhere around 2 or 3 and it shows that there is some positive
skewness in the data.
Using the rule of thumb in Exercise 1, the histogram also shows that there is a
lot of spread/variation in this data.
8
7
6
5
4
3
2
1
0
.20
.10
.00
Number
Relative
Frequency
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a.
57
.
192
x
,
189
~
x
. The mean is larger than the median, but they are still fairly close together.
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 Spring '08
 Staff
 Frequency, Histogram, RSL

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