ME300Lecture22

ME300Lecture22 - Lecture 22 : Energy Analysis of Reactions...

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22.1 Lecture 22 : Energy Analysis of Reactions Actual Combustion Analysis: » Note that complete combustion (as defined in the last lecture) will not occur in actual combustion processes even with excess air. » For example: CH 4 + 2.5 (O 2 + 3.76 N 2 ) 2 H 2 O + 0.97 CO 2 + 0.03 CO + 0.265 O 2 + 9.4 N 2 » Why? – Incomplete mixing of reactants – Insufficient time for combustion process
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22.2 Continue Actual Combustion Analysis Analysis of Actual Combustion Process: » The products of an actual combustion process are usually determined through measurements (e.g., gas chromatograph, infrared analyzer) » The composition of the products is typically given in terms of mole fractions (volume fractions) for the “dry” gaseous mixture (neglecting the water vapor) » The chemical reaction can then be determined from the element balances given the product composition
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22.3 Example 22.1 Given: » Combustion reaction: a CH 4 + b (O 2 + 3.76 N 2 ) c H 2 O + d CO 2 + e CO + f O 2 + g N 2 » From product analysis: Find: a, b, c 2 22 CO CO ON de y 0.097 y 0.005 d e f g d e f g fg y 0.0295 y 0.8685 d e f g d e f g
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22.4 Continue Example 22.1
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22.5
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This document was uploaded on 04/23/2011.

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ME300Lecture22 - Lecture 22 : Energy Analysis of Reactions...

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