# Hw4sol - Homework#4 1 i ME363Solutions Sand casting VT n =C 643 30 n =574 60 n 642 60 2 n = 1249 = 574 30 ln1.249 n= = 0.32 ln2 C=642 30 0.32 n =

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Homework #4 ME 363 Solutions 1. i) () n nn n n 0.32 Sand casting VT =C 643 30 =574 60 60 642 2 1249 30 574 ln1.249 n 0.32 ln2 C=642 30 1907 ⋅⋅ ⎛⎞ == ⎜⎟ ⎝⎠ ⋅= ii) ( ) () () ( ) n 0.33 permanent molding 517 30 411 60 60 517 1.258 30 411 n 0.33 C 517 30 1588.3 ∴= iii) ( ) n 0.231 PMC with flood cooling 554 30 472 60 60 554 1.174 30 472 n=0.231 C= 554 30 1215.4 = =

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2. i) () tc o min o min 0.125 n min r High speed steel. 1C T C b) T = 1 nC 30 1.5 3 1 60 = 1 42min 30 0.125 60 C 200 a) V 125.35 fpm T 42 DL 2.25 11.5 c) CT 12Vf 12 125.35 0 ππ ⎛⎞ + ⎜⎟ ⎝⎠ −= == = ⋅⋅ 1o co 2 t 3 4 1234 5.4min .01 30 d) C =CT C =5.4x \$2.7 60 TCC T20 . 55 . 4 C = \$0.129 T4 2 CxCT 1 .5 5 .4 C = \$0.193 2 26 0 C = 0.5 \$0.6 100 C=C +C +C +C =\$3.69 e) Total time = ×= ×× × × × × c CT CT 100+T 100+2 100+2 60 T 5.4 =5.4x100+3 100+200+120=898.6 min 42 Production rate 100 parts parts 0.11 6.67 min hour 898.6 × × ×
ii) () tc o min o min 0.25 n min r Carbide 1C T C b) T = 1 nC 30 11 1 60 = 1 9min 30 0.25 60 C 1500 a) V 866.03 fpm T 9 DL 2.25 11.5 c) CT 0.78min 12Vf 12 866.03 0.01 ππ ⎛⎞ + ⎜⎟ ⎝⎠ −= == = ⋅⋅ = 1o co 2 t 3 4 1234 c 30 d) C =CT C =0.78 \$0.39 60 T C CT 1 0.5 0.78 C = \$0.043 T9 C CT 1 0.78 C = \$0.087 26 0 C = 0.5 \$0.6 100 C=C +C +C +C =\$1.12 e) Total time CT CT 100+T T ×× = × × × ×= 100+2 100+2 60 0.78 =0.78 100+1 100+200+120=406.7 min 9

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## This document was uploaded on 04/23/2011.

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Hw4sol - Homework#4 1 i ME363Solutions Sand casting VT n =C 643 30 n =574 60 n 642 60 2 n = 1249 = 574 30 ln1.249 n= = 0.32 ln2 C=642 30 0.32 n =

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