Lecture_9

Lecture_9 - Lecture 9-1 Lecture Both B and E present FE =...

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Lecture 9 Lecture 9 -1 Both B and E present B Fq v B down = E F p qE u = E v B ∴= when balanced velocity selector
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Lecture 9 Lecture 9 -2 Physics 219 – Question 1 – February 14, 2011 a) Increase E b) Increase B c) Turn B off d) Turn E off e) Nothing A proton (charge +e) comes horizontally into a region of perpendicularly crossed, uniform E and B fields as shown. In this region, it deflects upward as shown. What can you do to change the path so it remains horizontal through the region?
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Lecture 9 Lecture 9 -3 Magnetic Force on a Current • Consider a straight current-carrying wire in the presence of a magnetic field B . • There will be a force on each of the charges moving in the wire. What will be the total force F on a length L of the wire? • Current is made up of n charges/volume , each carrying charge q < 0 and moving with velocity v through a wire of cross-section A . qv B × K JK Force on each charge = () Fn A L q v B = × Total force: K in A v q = Current: F iL B = × J KJ K A
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Lecture 9 Lecture 9 -4 Magnetic Force on a Current Loop – Force on top path cancels force on bottom path ( F = IBL ) – Force on right path cancels force on left path.
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Lecture_9 - Lecture 9-1 Lecture Both B and E present FE =...

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