Phys_219_Lecture_15_

Phys_219_Lecture_15_ - Lecture 15Lecture 15-1 Total...

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Lecture 15 Lecture 15-1 Total Internal Reflection All light can be reflected, none refracting, when light travels from a medium of higher to lower indices of refraction. g glass (n 1 5) to air (n 1 0) e.g., glass (n 1 =1.5) to air (n 2 =1.0) sin 1 2 n medium 2 1 sin 2 1 n 21 But cannot be greater than 90 ° ! medium 1 In general, if sin 1 > ( n 2 / n 1 ), we have NO refracted ray; we have TOTAL INTERNAL REFLECTION .  1 sin / c nn Critical angle above which this occurs.
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Lecture 15 Lecture 15-2 Examples 1 1 sin 48.8   Fish’s view of the world 1.33 c   Prism used as reflectors 1 1 sin 41.8 5 c (e.g., glass ith n=1 5) 1.5 with n=1.5) Optical fiber 1 1.5 n 69 6 (e.g., n core =1.5,n cladding =1.5) c sin 69.6 1.6 c 
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Lecture 15 Lecture 15-3 Physics 219 – Question 1 – March 7, 2011. A monochromatic light ray passes through 5 different media with parallel interfaces as shown. Which medium (layer) has the smallest index of refraction? D E AB C
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Lecture 15 Lecture 15-4 Physics 219 – Question 2 – March 7, 2011. The critical angle for total internal reflection for a glass-air interface (see below) is 40 What is the index of refraction interface (see below) is 40 .
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Phys_219_Lecture_15_ - Lecture 15Lecture 15-1 Total...

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