Lecture02 - Lecture 2 Chapter 13. Electric Field...

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1 Lecture 2 Chapter 13. Electric Field * Superposition of Electric Fields Coulomb’s Law of Electro-static Force and the permittivity constant is ε o = 8.55 x 10 12 C 2 / Nm 2 F = 1 4 πε 0 Q 1 Q 2 r 2 ˆ r 2 2 1 0 4 1 r Q Q F F = = Force on “2” by “1” Force repulsive 1 + + 2 r F 21 Force attractive + - 2 r 1 F 21 How Strong is the Coulomb’s Force? Compare Coulomb and gravitational forces for a proton and electron in a hydrogen atom Electric field due to a Point Charge r r q E ˆ 4 1 2 1 0 1 = For a Point Charge: - + r 0, E →∞ Point charge does not exert field on itself!
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2 Electric Field 0 q F E = + πε = 2 2 2 2 1 2 1 1 0 0 r ˆ r q r ˆ r q 4 q F Observation: The net Coulomb force on a given charge is always proportional to the strength of that charge. q 0 q 1 q 2 F 1 F F 2 test charge Define the electric field , which is independent of the test charge, q 0 , and depends only on position in space: q 1 and q 2 in F are the sources of the electric field, q 0 is the test charge 2 1 F F F + = Electric Field E = 1 4 πε 0 q i r i 2 ˆ r i
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This note was uploaded on 04/23/2011 for the course PHYS 272 taught by Professor K during the Spring '07 term at Purdue University-West Lafayette.

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Lecture02 - Lecture 2 Chapter 13. Electric Field...

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