{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Lecture_06_(Chap.16)

Lecture_06_(Chap.16) - Register your clicker if you havent...

Info iconThis preview shows pages 1–9. Sign up to view the full content.

View Full Document Right Arrow Icon
Register your clicker if you haven’t done it. No lecture this Wednesday, Feb. 2. Exam 1 on Feb 15 (Tuesday), 8-9:30 PM, 1
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
E of Uniformly Charged Thin Rod In vector form: E y 0 1 4  0 Q r r 2 L / 2 2 ˆ r At center plane Check the results: Direction Units Special case r >> L: E y 0 1 4  0 Q r 2 ˆ r Special case 2: L >> r (very long rod) 1 2 Q / L ˆ E y 0 4  0 r r 1/ r dependence! Q / L – linear charge density 2
Background image of page 2
E of Uniformly Charged Rod At distance r from midpoint along a line perpendicular to the rod: E 0 1 Q ˆ r y 4  0 r r 2 L / 2 2 F l d For very long rod: E 1 4 2 Q / L ˆ r  0 r Field at the ends: Numerical calculation 3
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
General Procedure for Calculating Electric Field of Distributed Charges 1. Cut the charge distribution into pieces for which the field is known 2. Write an expression for the electric field due to one piece (i) Choose origin (ii) Write an expression for Δ E and its components 3. Add up the contributions of all the pieces (i) Try to integrate symbolically (ii) If impossible – integrate numerically 4. Check the results: (i) Direction (ii) Units (iii) Special cases 4
Background image of page 4