{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

quiz3-key

quiz3-key - standards The results from 100 samples are...

This preview shows page 1. Sign up to view the full content.

Quiz 3. February 4, 2011 Seat # _________ Name: ___ < KEY > ___ Closed book and notes. No calculators. Recall: (Total Probability) If B 1 , B 2 , . . . , B n partition the sample space S , then P( A ) = P( A | B 1 ) P( B 1 ) + P( A | B 2 ) P( B 2 ) + . . . + P( A | B n ) P( B n ). Questions 1, 2, and 3 (2 pts each). In each line of the proof, choose one of these answers: (a) mutually exclusive events (b) independent events (c) same event (d) one event lies inside the other event (e) multiplication rule (f) Bayes’s Rule P( A ) = P[( A B 1 ) ( A B 2 ) . . . ( A B n )] (1) ___ < (c) > ___ = P( A B 1 ) + P( A B 2 ) + . . . + P( A B n ) (2) ___ < (a) > ___ = P( A | B 1 ) P( B 1 ) + P( A | B 2 ) P( B 2 ) + . . . + P( A | B n ) P( B n ) (3) ___ < (e) > ___ For Questions 4 and 5, consider Montgomery and Runger’s Problem 2–63. Samples of emissions from three suppliers are classified for conformance to air-quality
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: standards. The results from 100 samples are summarized in the table. conforms iiiiiiiiiiiiiii yes no 1 22 8 supplier 2 25 5 3 30 10 Consider the experiment of choosing one of the 100 samples, each with equal likelihood. Let A denote the event that the chosen sample conforms to specifications. Let B i denote the event that the chosen sample is from supplier i , for i = 1, 2, 3. 4. (2 pts) T ← F P( B 1 ) + P( B 2 ) + P( B 3 ) = 1. 5. (2 pts) T F ← B 1 and B 2 are independent events. ______________________________________________________________________ Write on the back any concerns. (Or something humorous.) IE 230 – Page 1 of 1 – Schmeiser...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online