This preview shows page 1. Sign up to view the full content.
Unformatted text preview: E( X ) = (1)(0.1) + (1.5)(0.3) + (1.5)(0.2) + (2.5)(0.15) + (3)(0.25) = 1.975 ____________________________________________________________ 4. (2 points) Determine the value of f Y  X = 1.5 (1) = P( Y = 1  X = 1.5). ____________________________________________________________ f Y  X = 1.5 (1) = P( Y = 1  X = 1.5) = P( X = 1.5, Y = 1) / P( X = 1.5) = P( X = 1.5, Y = 1) / [(P( X = 1.5, Y = 2) + P( X = 1.5, Y = 3)] = 0.0 / (0.3 + 0.2) = 0.0 ____________________________________________________________ 5. (2 points) T F X and Y are independent. ______________________________________________________________________ Write on the back any concerns about the weekly quizzes or the course in general. IE 230 Page 1 of 1 Schmeiser...
View
Full
Document
This note was uploaded on 04/25/2011 for the course IE 230 taught by Professor Xangi during the Spring '08 term at Purdue UniversityWest Lafayette.
 Spring '08
 Xangi

Click to edit the document details