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Unformatted text preview: HW Solutions 3 - 8.01 MIT - Prof. Kowalski Topics: circular and relative motion and Newtons first two laws. 1) 4.4 Please refer to figure 4.26 p.148. This is just a vector algebra problem and the problem is not inter- ested in dynamics. The vector here is the force! a) F x = F cos where is the angle that the rope makes with the ramp ( = 30 o in this problem),so F = | F | = F x cos = 60 cos 30 = 69 . 3 N. b) F y = F sin = F x tan = 34 . 6 N. c) The problem in part a and b is not interested in the force along or perpendicular to the ground. So, as long as we dont change the angle with respect to the ramp the answer to part a and b would not change. d) F makes an angle 50 o with respect to ground so the F gx and F gy is derived from: F gx = F cos g = 69 . 3 cos 50 o = 53 . 1 N. F gy = F sin g = 69 . 3 sin 50 o = 44 . 5 N. 1 2) 4.30 a) v ave between two points , e.g. f and i, for a constant acceleration is v ave = v f + v i 2 . Here v f = 0...
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This note was uploaded on 04/22/2011 for the course PHYS 1441 taught by Professor White during the Spring '08 term at UT Arlington.
- Spring '08