1271Chapter 331. Since, we findfis equal to899292(3.0 10 m/s)(0.0100 10m)7.49 10 Hz.(632.8 10m)cc2. (a) The frequency of the radiation isfc301010106 4104 7108563.( .)( ..m / sm)Hz.(b) The period of the radiation isTf114 7102123323.minHzss.3. (a) From Fig. 33-2 we find the smaller wavelength in question to be about 515 nm.(b) Similarly, the larger wavelength is approximately 610 nm.(c) From Fig. 33-2 the wavelength at which the eye is most sensitive is about 555 nm.(d) Using the result in (c), we have8143.0010 m/s5.41 10Hz555 nmcf.(e) The period isT= 1/f= (5.411014Hz)–1= 1.8510–15s.4. In air, light travels at roughlyc= 3.0108m/s. Therefore, fort= 1.0 ns, we have adistance ofdct( ..30100 3089m / s)(1.010s)m.5. Iffis the frequency andis the wavelength of an electromagnetic wave, thenf= c.The frequency is the same as the frequency of oscillation of the current in theLCcircuitof the generator. That is,fLC1 2/, whereCis the capacitance andLis theinductance. Thus