# ch33 - Chapter 33 1. Since , we find f is equal to 8 9 c c...

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1271Chapter 331. Since, we findfis equal to899292(3.0 10 m/s)(0.0100 10m)7.49 10 Hz.(632.8 10m)cc2. (a) The frequency of the radiation isfc301010106 4104 7108563.( .)( ..m / sm)Hz.(b) The period of the radiation isTf114 7102123323.minHzss.3. (a) From Fig. 33-2 we find the smaller wavelength in question to be about 515 nm.(b) Similarly, the larger wavelength is approximately 610 nm.(c) From Fig. 33-2 the wavelength at which the eye is most sensitive is about 555 nm.(d) Using the result in (c), we have8143.0010 m/s5.41 10Hz555 nmcf.(e) The period isT= 1/f= (5.411014Hz)–1= 1.8510–15s.4. In air, light travels at roughlyc= 3.0108m/s. Therefore, fort= 1.0 ns, we have adistance ofdct( ..30100 3089m / s)(1.010s)m.5. Iffis the frequency andis the wavelength of an electromagnetic wave, thenf= c.The frequency is the same as the frequency of oscillation of the current in theLCcircuitof the generator. That is,fLC1 2/, whereCis the capacitance andLis theinductance. Thus
CHAPTER 3312722LCc.The solution forLis292212222128550 10m5.00 10H.4417 10F2.998 10 m/sLCcThis is exceedingly small.6. The emitted wavelength iscf2cLC22.998108m/s0.253106H30.01012F5.19 m.7. The intensity is the average of the Poynting vector:ISavgcBm2203.0108m/s1.0104T22 1.26106H/m21.2106W/m2.8. The intensity of the signal at Proxima Centauri isIP4r23.0106W44.3ly9.461015m/ly21.41028W/m2.9. IfPis the power andtis the time interval of one pulse, then the energy in a pulse isEPt1001012W1.0109s1.0105J.10. The amplitude of the magnetic field in the wave isBmEmc1.80104V/m2.998108m/s6.001013T.11. (a) The amplitude of the magnetic field is9982.0V/m6.67 10T6.7 10T.2.998 10 m/smmEBc
1273(b) Since the-waveEoscillates in thezdirection and travels in thexdirection, we haveBx= Bz= 0. So, the oscillation of the magnetic field is parallel to theyaxis.(c) The direction (+x) of the electromagnetic wave propagation is determined byEB. Ifthe electric field points in +z, then the magnetic field must point in the –ydirection.With SI units understood, we may write151589152.0cos 10/cos103.0106.710cos 10ymtx cxBBtcxtc12. (a) The amplitude of the magnetic field in the wave isBmEmc

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