homework11

homework11 - savage (jws775) – Homework #11 – Holcombe...

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Unformatted text preview: savage (jws775) – Homework #11 – Holcombe – (52460) 1 This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points The equilibrium constant for the reaction 2 Hg( ℓ ) + 2 Cl − (aq) + Ni 2+ (aq) → Ni(s) + Hg 2 Cl 2 (s) is 5.6 × 10 − 20 at 25 ◦ C. Calculate the value of E ◦ for a cell utilizing this reaction. 1.- 0.57 V correct 2. + 1.14 V 3.- 1.14 V 4.- 0.25 V 5. + 0.57 V Explanation: 002 10.0 points The standard voltage of the cell Ag(s) | AgBr(s) | Br − (aq) || Ag + (aq) | Ag(s) is +0.73 V at 25 ◦ C. Calculate the equilibrium constant for the cell reaction. 1. 3 . 9 × 10 − 29 2. 2 . 2 × 10 12 correct 3. 2 . × 10 − 15 4. 5 . 1 × 10 14 5. 4 . 6 × 10 − 13 Explanation: 003 10.0 points Calculate the reduction potential for the Zn 2+ | Zn electrode if the Zn 2+ concentra- tion is 2 × 10 − 3 M. The standard potential for Zn 2+ + 2 e − → Zn is- . 7628 V. 1.- . 842 V correct 2.- 1 . 844 V 3.- . 922 V 4.- 1 . 684 V Explanation: [Zn 2+ ] = 2 × 10 − 3 M E = E- parenleftbigg . 0592 n parenrightbigg log Q =- . 7628 V- parenleftbigg .....
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This note was uploaded on 04/22/2011 for the course CHEM 302 taught by Professor Mccord during the Spring '10 term at University of Texas.

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homework11 - savage (jws775) – Homework #11 – Holcombe...

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