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Unformatted text preview: 1 Chapter 11 Angular Momentum 2 Angular Momentum Linear momentum: p = mv Angular momentum: L = I = I = F = ma = dL dt dp dt The rate of change of angular momentum of a particle is equal to the net torque applied to it. 3 Vector Cross Product C = A x B = AB sin 4 Cross Product A = A x i + A y j + A z k B = B x i + B y j + B z k i j k A x B = A x A y A z B x B y B z = ( A y B z A z B y ) i + ( A z B x A x B z ) j + ( A x B y A y B x ) k 5 L vector is parallel to vector 6 7 ext = dL dt The total angular momentum of a rotating body remains constant if the net external torque acting on it is zero . is valid only when torque and angular momentum are calculated with respect to center of mass! 8 Conceptual Example A person stands, hands at the side, on a platform that is rotating at a rate of 1.30 rev/s. If the person now raises his arms to the horizontal position, the speed of rotation decreases to 0.80 rev/s. ( a ) Why does this occur? ( b ) By what factor has the moment of inertia of the person changed? 9 When the skater pulls her arms in, she is decreasing her moment of inertia. 10 Conceptual Example Spinning bicycle wheel. A student is holding a spinning bicycle wheel standing on a stationary frictionless turntable. What will happen if the student suddenly flips the bicycle wheel over so that it is spinning in the opposite direction? is spinning in the opposite direction?...
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This note was uploaded on 04/23/2011 for the course JAPAN 7b taught by Professor Wallace during the Spring '11 term at University of California, Berkeley.
 Spring '11
 wallace

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