D32490-Chapter 8 Problems & Solutions

# D32490-Chapter 8 Problems & Solutions - CHAPTER 8...

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C HAPTER 8 Problems and Solutions EC 73 6. A fishing pole is 2.00 m long and inclined to the horizontal at an angle of 20.0° (Fig. P8.6). What is the torque exerted by the fish about an axis perpendicular to the page and passing through the hand of the person holding the pole? F IGURE P8.6 8.6 Resolve the 100-N force into components  parallel to and perpendicular to the rod, as ( 29 ( 29 100 N cos 20.0 37.0 54.5 N parallel F = ° + ° = and ( 29 ( 29 . 100 N sin 20.0 37.0 83.9 N perp F = ° + ° = The torque due to the 100-N force is equal to the sum of the torques of its components. Thus, ( 29 ( 29 ( 29 ( 29 54.5 N 0 83.9 N 2.00 m τ = - = 168 N m - ⋅

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CHAPTER 8 16. The principal forces acting on a foot when a person is squatting are shown in Figure P8.16. Determine the magnitude of the force F H exerted by the Achilles tendon on the heel at point H and the magnitude of the force F J exerted on the ankle joint at point J . F IGURE P8.16 8.16 Require that  0 τ Σ =  about an axis through point J  and perpendicular to the page. This gives ( 29 ( 29 ( 29 1 0 350 N 4.00 cm 0 H J F d F - + + = , or ( 29 ( 29 1 350 N 4.00 cm H F d = ( 29 ( 29 ( 29 350 N 4.00 cm 3.20 cm cos52.0 = = ° 711 N Then,  ( 29 ( 29 Σ = ⇒ ° - = 0   711 N sin 52.0 0 x J x F F , or ( 29 560 N J x F = . Also,
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D32490-Chapter 8 Problems & Solutions - CHAPTER 8...

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