Plug this into the 3rd eq rt2 using the 1st eq

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Unformatted text preview: ely, we could note that when the piston and the weight go from h1 to h2 they perform the work m2g (h1 –h2) on the gas, which results, according to the 1st law, to an increase of From the 2nd equation we have h2 = RT2/m2g . Plug this into the 3rd eq.: RT2 + Using the 1st eq: RT2 + and T2 = T1 Let’s see what happens when we remove the weight so that the total mass above the gas again becomes m1. All we need to do is to...
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