{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

First Midterm 8-9

First Midterm 8-9 - Physics 1 First Midterm Exam(AM Name 3...

Info icon This preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Physics 1 First Midterm Exam (AM) 1/27/2009 Name: 3 0" U T’ old 3 ,. 1. (This problem is worth 40 points.) A painter is standing on a platform that is being raised at constant speed. As the painter travels upward, he accidentally nudges a can of paint off the platform when it is a distance D above the ground. The can hits the ground a time T after it falls off the platform. You can ignore air resistance. (a) Using the axes below, draw a 31—: graph and a vy—t graph of the motion of the can of paint. On both graphs P label (1) the time when the can leaves the platform (ii) the time when the can is at its maximum height, and (iii) the time when the can hits the ground a... . ijgwamw @311 wtpw Si d7l’(i) W® HWIMM _' - like (iii ) @fosihu «at (i) f @. 2% col (ii) (Since 6M1; afras l“) *flfie: ‘ 6L Aid-wee “Kid-Ni. flfig‘; D belAa’ (:9 (hi) (Sit/tram 1: pain}: me— (111 “my? film; Q) to a (he QM [Ff +1231 109%“ ' . i2 is (b) Find the speed of the platform. Your answer should involve no quantities other than D, T, and g. (It may or may not involve all of these ) For full credit, show your work and draw a box around your answer. . Lt= SpeeoQafiriai-fim: iui‘l'mQ MVezlanateCawsz intact “m Lodle-Y- sauce-hm Y: 20)/'t'\/:7"wf 538:2 (Fwwwdk Mp”. 644W 1“- 0;; (:2 2 m-Pmlwf’b t» {Ml WW Md!“ (b) Find the speed of the can just before it hits the ground. Your answer should involve no quantities other than D, T, and g. (It may or may not involve all of these.) For full credit, show your work and draw a box around your answer. - T W (Ase away—31,“) Vay=LL= Eff—~21; ‘9M&) 7“ D (Wuelo-cnfi) V'T : “-81”: (Z); __ D3-8T= 3“"(fl—l) #3: 6 07H Physics 1 First Midterm Exam (AM) 1/27/2009 Name: S L UT. 5 1 E 2. (This problem is worth 40 points.) A ball is fired from the Time cliff is reach€d= ? (1 a, H S d t ”T = '1‘ ground at an angle 04) above the horizontal. The ball is thrown at pee a C], / exactly the right speed so that itjust reaches the top of a cliff of ’ height H. Air resistance can be ignored. (a) Find the elapsed time from when the ball is launched to when it just reaches the cliff. Your answer should involve no quantities other than H, 04,, and g. (It may or may not involve all of these.) For full credit, Show your work and draw a box around your answer. 9% (we Mathilda cl? .50 "5V =0 «*MCIEFE J ’ 7 wiébfi [Molifigi‘rm wan“ rat imae M39). Fmdz-e vT-efioiw, 924's, \5 V)’ = voy~8t 30 O = V0 3m 0% ~35 aural 3+7: Vasmfizyay. - - pita me to y—eaw‘m' ”We”; an, Lt: H, so 41: VOTJc- fight beam END-H“! 566w /’ 4—/ Y Vx: V0X= V0 C5? 0(0 Vader MM® [pl—5 your answer. : \ drew Clt 1 V7 = 0, $0 {fiat/2.107477 rs I‘M. 7L Xvi/tweak)“. O SMWO = = i4” 'B’Fgw’r (WA) VX Vomg sto my" ._ @C‘Otng’ Physics 1 First Midterm Exam (AM) 1/27/2009 Name: saw 7" m g 3. MULTIPLE CHOICE. (This problem is worth 20 points.) For each question, draw a circle around the one best answer. Each question is worth 4 points. There is no penalty for guessing. (a) Three vectors are given as shown. The scalar product 6—5;! is closest to is aavmmmm” it)?" steer, an Ito’ MW “03/ 4 “0M ”0“) (045 w are about (e)(8)(—a3)emW "5 ”6'“ (b) At a certain instant an object has the following velocity and acceleration: a = (2.00 m/s)i+(~3.00 m/s)}+(~3.00 m/s)12 6 a = (2.00 m/s2)i+(—4.00 m/sz)j+(8.00 Ill/52)]; At this instant, what is the object doing? .3 . ct: V at + V 4 V 6t (i) Speeding up and following a curved path V K K Y 2’ lb ,1! 2: (ii) Speeding up and moving in a straight line :— [(2.00) (’2 . 00) ‘l‘ (3. Ofi)(-‘i.00) + 63_m)(8.-00U in) owrng own an o ow1ng a curve pat w: 1/33 (iv) Slowing down and moving in a straig ine ___.[ 00 .410 ”29.0, m1 3 _ __ . L . (v) None of the above - LL " J A " 32' O M 1/33 (c) A projectile is launched at a 30° angle above the horizontal. Ignore air resistance. The projectile’s , L: acceleration is greatest at This is Mfi—aoiwe, so V9: Zara walla“ 90°aP4flL. -3: (i) at a point between the launch point and the high point of the trajectory (ii) at the high point of the trajectory ,i—r Li (iii) at a point between the high point of the trajectory and where it hits the round ( (iv) misleaging quest‘ifii n — :36 acceleration is the same (but nonzero) at all points along the trajectory i (v) mis ea ing ques lOl’l — e cce era ion is zero a a pomts a ong e trajectory Q a hallmark— “? PM) i (e (d) You drive a race car around a circular track of radius 200 m at a constant speed of 200 km/h. If you then 31" drive the same car around a different circular track of radius 100 m at a constant speed of 100 built, your acceleration will be _ 2 7. 2 aw=a w.aae=vWeecwwem (i) 8 times greater Ottad— 2d 0 V2 7. ' (ii) 4 times greater m/sz V2.50 RIM (iii) the same ' ._ l 2 _ i 1v as great "' (—2—- ‘ 2 _ E (v none of the above (e) Which of the following situations is impossible? (i) An object has constant nonzero velocity and changing acceleration. \ , _,. ‘3 (it) An object has velocrty directed east and acceleration directed east. l \II = Gaugizuoh ,1 (iii) An object has constant nonzero acceleration and changing velocity. + “J / (iv) An object has velocity directed east and acceleration directed west. ““43 (4321 g 5 €— E-P/fz. _ , (v) An object has zero velocity but nonzero acceleration. +64 01239? I (vi) More than one of the above. QCCBi m Ca“ 'i‘ 0% (tic H— dialfivi‘ Wham WatcCgngfiztl WW bartomem M (flea veioztflhi WJhI‘lL ham) ...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern