Rectilinear Motion with Constant Acceleration

Rectilinear Motion with Constant Acceleration - Rectilinear...

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Rectilinear Motion with Constant Acceleration Phys 116 Lab Section 432 with John Kelley Willem Wyndham, Alice Xu, Jared Layne Date: 1/26/2011 The work presented in this report is my own, and the data were obtained by my lab partners and myself during the lab period. Willem Wyndham Abstract
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These experiments were designed to measure the affects of constant acceleration due to gravity, g, which at ground level is 9.8 m/s 2 . In the first experiment we directly measured gravity using two differently weighted tennis balls. The balls were attached paper tape that struck the paper at even time intervals. Acceleration was found for each position and an average was taken to determine the approximate value of the gravitational constant. The averages of the balls accelerations were different (heavy ball and the light ball were 9.640 ± 0.093 m/s 2 , 8.633 ± 0.211 m/s 2 respectively) and which could be due to error or drag. The second experiment was a system of a hanger dragging a glider over an air track past two photogates. Using the formula V f 2 =V i 2 +2 a (Δx) we could measure the distances and the velocities and solve for a . We then shifted weight from the hanger to the hanger each trial and the more weight on the hanger, the higher the acceleration. This was due to the fact that the force of the system was based on the mass of the hanger times the gravity constant g , which is equal to the mass of the system times the measured a ’s. Graphing the F and a , we found the predicted mass of the system. Our relative error was 65.5%. While error played a role in both experiments they both served to help illustrate constant acceleration.
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Analysis Heavy Tennis Ball The velocity of the ball at time .0250 was calculated by adding up the distance from t=0 to .0500 then dividing it by that time interval. This is more explained in the discussion section later. Also this method was extended to find the acceleration by finding the change in velocity over an interval of .05 seconds then divided by that to find the acceleration of the middle point in time. Using this method you couldn’t find the first velocity at zero and thus the acceleration at t=0 and .0250. Values of acceleration differ from interval to the next due to error in measurement, which
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Rectilinear Motion with Constant Acceleration - Rectilinear...

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