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Unformatted text preview: Problem 1: Solution: a) Treatment degree of freedom = 3, therefore there are 4 treatments. Total degree of freedom is 30; therefore there are 30 data samples. The experiment design is shown in the following table: Treatments A B C D Number of Replications (7) (8) (9) (6) Besides, the error terms should be independent and identically normally distributed. b) Ho: the four treatments have the same bioactivity u g GGG g U U g g g 0.0003 At 0.01 level, g Therefore, the null hypothesis can be rejected at 0.01 level. c) G g , tij table is shown below: , Using Tukey method, at 0.01 level, g g 3.46 Comparing tij with 3.46, it can be observed that, at 0.01 level, AC an BC have statistically significant differences....
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This note was uploaded on 04/26/2011 for the course STATS 424 taught by Professor Peterqian during the Spring '11 term at Wisconsin.
 Spring '11
 PETERQIAN
 Replication

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