ch04 - Exercise 4.1 Subject: Degrees of freedom analysis...

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Unformatted text preview: Exercise 4.1 Subject: Degrees of freedom analysis for a three-phase equilibrium stage. Given: Equilibrium stage of Figure 4.35, with two feeds (one vapor, one liquid), vapor entering from stage below, liquid entering from stage above, three exiting streams (one vapor, two liquid), and heat transfer. Assumptions: Equilibrium stage Find: (a) List and count of variables. (b) List and count of equations. (c) Number of degrees of freedom. (d) List of reasonable set of design variables. Analysis: (a) With 4 streams in and 3 streams out, and heat transfer, Number of variables = N V = 7( C +3) + 1 = 7 C + 22 The variables are 7 total flow rates, 7 temperatures, 7 pressures, 1 heat transfer rate and C mole fractions for each of the 7 streams. (b) The equations are: C Component material balances 1 Energy balance 2 Pressure identity equations for the 3 exiting streams 2 Temperature identity equations for the 3 exiting streams 7 Mole fraction sums (one for each stream) 2 C Phase equilibrium equations: K y x K y x i i i i i i I I II II and = = Total number of equations = N E = 3 C + 12 (c) Degrees of freedom = N D = N V- N E = (7 C + 22) - (3 C + 12) = 4 C +10 (d) A possible set of specifications is: For each entering stream: Total flow rate, temperature, pressure, and C-1 mole fractions, which totals 4( C + 2) = 4 C + 8 For the remaining 2 variables, choose any combination of Q , temperature of one of the three exiting streams, and/or pressure of one of the three exiting streams. Exercise 4.2 Subject: Determination of uniqueness of three different operations. Given: (a) An adiabatic equilibrium stage with known vapor and liquid feed streams, and known stage temperature and pressure. (b) Same as (a), except that stage is not adiabatic. (c) Partial condenser using cooling water, with known vapor feed (except for flow rate), outlet pressure, and inlet cooling water flow rate. Assumptions: Exiting streams in equilibrium. Find: (a) Whether composition and amounts of exiting vapor and liquid can be computed. (b) Same as part (a). (c) Whether cooling water rate can be computed. Analysis: (a) With two steams in and two out, number of variables = N V = 4( C + 3) = 4 C + 12 Equations are: C Component material balances 1 Energy balance 1 Pressure identity for 2 exiting streams 1 Temperature identity for 2 exiting streams 4 Mole fraction sums for 4 streams C Phase equilibrium equations Therefore, number of equations = N E =2 C + 7 Degrees of freedom = N D = N V- N E = (4 C + 12) - (2 C + 7) = 2 C +5 Given specifications are: 2 C + 4 variables for the two feed streams. Only one specification left. Therefore can not specify both T and P for exiting streams ....
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This note was uploaded on 04/27/2011 for the course CHEM 101 taught by Professor Suh during the Spring '11 term at University of Toronto- Toronto.

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ch04 - Exercise 4.1 Subject: Degrees of freedom analysis...

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