SCALE:
20 N = 1 inch
W 68.7
0
S
95N
F2
85N
F3
W 29
0
N
35N
F1
E 66.2
0
N
SCALE:
20 N = 1 inch
W 41.1
0
S
55N
F2
R (Resultant)
W 13.8
0
N
100N
F3
50N
F1
W 77.9
0
N
E101RESOLUTION OF FORCES
PHY10L/A5
Prof. Bernard Aguirre
INTERPRETATION OF RESULT
This experiment deals with the fundamental area of physics, the resolution of force. The experiment aims
to determine the resultant force of concurrent forces using different methods of analyzing. Force acting on
a certain body, namely the ring, varies according to mass of load applied on it (magnitude) and to the
direction where it is positioned (direction). From the statement said, force can be and is considered as a
vector quantity.
In the experiment, three loads on string with masses were used to exert measurable forces on a ring at the
center of the force table. They were also adjusted in measurable angles. A fourth string, also with load
was place against the other, which is called the equilibrant. It is because it function to neutralize or to
contradict the force exerted by the other three by means of supplying the same amount of magnitude but
opposite in direction. This is made to achieve the static equilibrium. The indication of the equilibrium is
when the ring, subjected to force is at the center. In simple terms, the sum of the three vectors (force
exerted) will be the resultant vector, which is equal to the force exerted by the stationary spring but of
opposite direction.
By considering the force exerted by the three strings, we could calculate the resultant vector using
graphical (polygon) and analytical (component) method of analysis. Graphical method uses graphing of
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 Spring '11
 Agguire
 Physics, Force, Prof. Bernard Aguirre, PHY10L/A5 Prof. Bernard

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