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# E101 - E101-RESOLUTION OF FORCES 50N 55N CALE 100N S 85N...

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SCALE: 20 N = 1 inch W 68.7 0 S 95N F2 85N F3 W 29 0 N 35N F1 E 66.2 0 N SCALE: 20 N = 1 inch W 41.1 0 S 55N F2 R (Resultant) W 13.8 0 N 100N F3 50N F1 W 77.9 0 N E101-RESOLUTION OF FORCES PHY10L/A5 Prof. Bernard Aguirre INTERPRETATION OF RESULT This experiment deals with the fundamental area of physics, the resolution of force. The experiment aims to determine the resultant force of concurrent forces using different methods of analyzing. Force acting on a certain body, namely the ring, varies according to mass of load applied on it (magnitude) and to the direction where it is positioned (direction). From the statement said, force can be and is considered as a vector quantity. In the experiment, three loads on string with masses were used to exert measurable forces on a ring at the center of the force table. They were also adjusted in measurable angles. A fourth string, also with load was place against the other, which is called the equilibrant. It is because it function to neutralize or to contradict the force exerted by the other three by means of supplying the same amount of magnitude but opposite in direction. This is made to achieve the static equilibrium. The indication of the equilibrium is when the ring, subjected to force is at the center. In simple terms, the sum of the three vectors (force exerted) will be the resultant vector, which is equal to the force exerted by the stationary spring but of opposite direction. By considering the force exerted by the three strings, we could calculate the resultant vector using graphical (polygon) and analytical (component) method of analysis. Graphical method uses graphing of

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E101 - E101-RESOLUTION OF FORCES 50N 55N CALE 100N S 85N...

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